NCERT Solutions Exercise 3
Question 1:
Find the transpose of each of the following matrices:
Answer:
Question 2:
- (A + B)’ = A’ + B’
- (A - B)’ = A’ - B’
Answer:
We have
- A + B
Hence, we have verified that (A+B)’ = A’ + B’
(ii) A – B
Hence, we have verified that (A - B)’ =A’ – B’.
Question 3:
- (A + B)’ = A’ + B’
- (A - B)’ = A’ - B’
Answer:
(i) It is known that A = (A’)’
Therefore, we have:
Thus, we have verified that (A+B)’ = A’ + B’
(ii)
Thus we have verified that (A-B)’= A’ – B’
Question 4:
Answer:
We known that A = (A’)’
Question 5:
For the matrices A and B, verify that (AB)′ = B’A’ where
Answer:
Hence, we have verified that (AB)’ = B’A’.
Hence, we have verified that (AB)’=B’A’.
Question 6:
Answer:
(i)
Hence, we have verified that A’A = I
(ii)
Hence, we have verified that A’A=I.
Question 7:
(i) Show that the matrix is a symmetric matrix
(ii) Show that the matrix is a skew symmetric matrix
Answer
Hence, A is a symmetric matrix.
(ii) We have:
Hence, A is a skew-symmetric matrix.
Question 8:
For the matrix verify that
- (A+A’) is a symmetric matrix
- (A-A’) is a skew symmetric matrix
Answer:
Hence, (A + A’) is a symmetric matrix.
Hence, (A – A’) is skew-symmetric matrix.
Question 9:
Find ½ (A + A’) and ½ (A - A’), When
Answer:
The given matrix is
Question 10:
Express the following matrices as the sum of a symmetric and a skew symmetric matrix:
Answer:
(i)
Thus, P = ½ (A+A’) is a symmetric matrix.
Thus, Q = ½ (A-A’) is a skew-symmetric matrix.
Representing A as the sum of P and Q:
(ii)
Thus, P = ½ (A+A’)
Thus, Q = ½ (A-A’) is a skew-symmetric matrix.
Representing A as the sum of P and Q:
(iii)
Thus, P = ½ (A+A’) is a symmetric matrix.
Thus, Q = ½ (A-A’) is a skew-symmetric matrix.
(iv)
Thus, P = ½ (A+A’) is a symmetric matrix.
Thus, Q = ½ (A-A’) is a skew-symmetric matrix.
Representing A as the sum of P and Q:
Question 11: If A, B are symmetric matrices of same order, then AB − BA is a
A. Skew symmetric matrix
B. Symmetric matrix
C. Zero matrix
D. Identity matrix
Answer
The correct answer is A.
A and B are symmetric matrices, therefore, we have:
A’ = A and B’=B ….(1)
Consider (AB-BA)’ = (AB)’ – (BA)’ [(A-B)’ = A’ – B’]
= B’A’ – A’B’ [(AB)’ = B’A’]
= BA – AB [by (1)]
= (AB - BA)
∴ (AB - BA)’ = - (AB - BA)
Thus, (AB − BA) is a skew-symmetric matrix.
Question 12:
If , then A + A’ = I, if the value of a is
A. π/6
B. π/3
C. π
D. 3π/2
Answer:
The correct answer is B.
Now, A+A; = I
Comparing the corresponding elements of the two matrices, we have:
2 cos α = 1
⇒ cos α = 1/2 = cos (π/3)
∴ α = (π/3)