NCERT Solution Exercise 5

Question 1: Find the inverse of each of the matrices, if it exists.

Answer:

We know that A = IA

Question 2: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Question 3: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Question 4: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Question 5: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Question 6: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

 

Question 7: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = AI

Question 8: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Question 9: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Question 10: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = AI

Question 11: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = AI

Question 12: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Now, in the above equation, we can see all the zeros in the second row of the matrix on the L.H.S.

Therefore, A −1 does not exist.

 

Question 13: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Question 14: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Applying R1→ R1-1/2 R2, we have:

Now, in the above equation, we can see all the zeros in the first row of the matrix on the L.H.S.

Therefore, A −1 does not exist.

 

Question 16: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Applying R2 → R2 + 3R1 and R3 → R3 − 2R1, we have:

Applying R1 → R1 + 3R3 and R2 → R2 + 8R3, we have:

Applying R3 → R3 + R2, we have:

Applying R3 → 1/25 R3, we have:

Applying R1 → R1 - 10R3 and R2 → R2 - 21R3, we have:

Question 17: Find the inverse of each of the matrices, if it exists.

Answer

We know that A = IA

Applying R1 → ½  R1, we have:

Applying R2 → R2 - 5R1, we have:

Applying R3 → R3 – R2, we have:

Applying R3 → 2R3, we have:

Applying R1 → R1 + (1/2) R3, and R2 → R2 + (5/2) R3, we have:

Question 18: Matrices A and B will be inverse of each other only if

A. AB = BA

B. AB = BA = 0

C. AB = 0, BA = I

D. AB = BA = I

Answer

Answer: D We know that if A is a square matrix of order m, and if there exists another square matrix B of the same order m, such that AB = BA = I, then B is said to be the inverse of A. In this case, it is clear that A is the inverse of B.

Thus, matrices A and B will be inverses of each other only if AB = BA = I.

Related Keywords
12    IIT    Math    Matrices    NCERT Solution Exercise 5