NCERT Solution Exercise 4
Question 1: Find the inverse of each of the matrices, if it exists.
Answer:
We know that A = IA
Question 2: Find the inverse of each of the matrices, if it exists.
Answer
We know that A=IA
Question 3: Find the inverse of each of the matrices, if it exists.
Answer
We know that A=IA
Question 4: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Question 5: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Question 6: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Question 7: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = AI
Question 8: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Question 9: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Question 10: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = AI
Question 11: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = AI
Question 12: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Now, in the above equation, we can see all the zeros in the second row of the matrix on the L.H.S.
Therefore, A −1 does not exist.
Question 13: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Question 14: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Applying R1 → R1 – ½ R2, we have:
Now, in the above equation, we can see all the zeros in the first row of the matrix on the L.H.S.
Therefore, A −1 does not exist.
Question 16: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Applying R2 → R2 + 3R1 and R3 → R3 − 2R1, we have:
Applying R1 → R1 + 3R3 and R2 → R2 − 8R3, we have:
Applying R3 → R3 + R2, we have:
Applying R3 → 1/25 R3, we have:
Applying R1 → R1 - 10R3 and R2 → R2 − 21R3, we have:
Question 17: Find the inverse of each of the matrices, if it exists.
Answer
We know that A = IA
Applying R1→ ½ R1, we have:
Applying R2→ R2-5R1, we have:
Applying R3→ R3-R2, we have:
Applying R3→ 2R3, we have:
Applying R1→ R1+ ½ R3, and R2→ R2+ 5/2 R3,we have:
Question 18: Matrices A and B will be inverse of each other only if
A. AB = BA B. AB = BA = 0
C. AB = 0, BA = I D. AB = BA = I
Answer
Answer: D We know that if A is a square matrix of order m, and if there exists another square matrix B of the same order m, such that AB = BA = I, then B is said to be the inverse of A. In this case, it is clear that A is the inverse of B.
Thus, matrices A and B will be inverses of each other only if AB = BA = I